Messages

1

Audio / Re: AW: How are Samples, ChannelCount and SampleRate connected?

« on: April 05, 2015, 05:42:09 pm »

If you want to extract one channel, you need to go over the sample data and only pick every other sample.

Great, so if I for example want to create stereo sound where only left speaker is loud and right is quiet my Samples array would be

{1879, 0, 3751, 0, 5608, 0, 7444, 0, 9250, 0} //only a lot longer ofc

and when I want to play the same thing on both speakers, I would create

{1879, 1879, 3751, 3751, 5608, 5608, 7444, 7444, 9250, 9250}

Thank you for help!

2

Audio / How are Samples, ChannelCount and SampleRate connected?

« on: April 05, 2015, 09:45:25 am »

I'm having a problem and I can't find a solution. Long story short, I have 9 seconds long .wav sound with 2 channels and 48000 SampleRate. Then I try to do convolution (which is correct from tests I did) and save these new Samples in new SoundBuffer and later in Sound and play again. Firstly I was using these code:

song = new Sound(new SoundBuffer(y, song.SoundBuffer.ChannelCount, song.SoundBuffer.SampleRate));

and as you can see, I just copied old ChannelCount and SampleRate. It didn't work, SampleRate of new SoundBuffer was 0. Then I found out that if I do this:

song = new Sound(new SoundBuffer(y, 1, song.SoundBuffer.SampleRate));

I can play that new Sound but speed is half of that of original. Lastly, I changed the code to this:

song = new Sound(new SoundBuffer(y, 1, song.SoundBuffer.SampleRate * 2));

and now everything's fine, the Sound can be played and length is as it should be. But I still don't know the actual solution to my problem. What if I want to do different convolutions for different channels, how can I recognise those channels in Samples array? And how do I need to save these modified Samples in new array in order to play them as SoundBuffer with 2 channels?