C++ problem with sf::Event::TextEntered

[pauliuc]

Hello all,

i am making a text box, and a small problem occured.

Code: [Select]

if( event.Type == sf::Event::KeyPressed )
{
       if( event.Key.Code == sf::Key::Back )
       {
            text.erase( text.size( ) - 1 );
       }
       else if( event.Key.Code == sf::Key::Return )
       {
            text += "\n";
       }
}
else if( event.Type == sf::Event::TextEntered )
{
      text += ( char )event.Text.Unicode;
}

The problem is that sf::Key::Back is ignored, when i type text. I figured out that its the problem with sf::Event::TextEntered because it takes backspace as text entered( ? ). How can i avoid that?

[Lupinius]

Since BackSpace is a character you can sort it out. It has the value 8 if I remember correctly.

Code: [Select]

if (event.Text.Unicode != 8)
    text += ( char )event.Text.Unicode;

[pauliuc]

thanks i will try that  :wink:

[Hiura]

You may want to check for only valid input, like [a-z] and [0-9] ranges + some other ranges (because there are much more key which doesn't have a printable value like backspace).

Refer to an UTF charset list to know the ranges (or search this forum).

[Mindiell]

If you look closely at the documentation, you can see this :

Code: [Select]

class Event
00205 {
00206 public :
00207
00212     struct KeyEvent
00213     {
00214         Key::Code Code;    
00215         bool      Alt;    
00216         bool      Control;
00217         bool      Shift;  
00218     };
00219
00224     struct TextEvent
00225     {
00226         Uint32 Unicode;
00227     };
Meaning that Event.Key.Code is to use only when a KeyEvent occurs, not a TextEvent !

[pauliuc]

It works with Lupinus suggested way  

Meaning that Event.Key.Code is to use only when a KeyEvent occurs, not a TextEvent !

im not using it when text event occurs... im using it when KeyPressed occurs.