Greater than or equal to location

[GAMINGBACON97]

I'm wondering how I would find if something is farther than a certain position. here is my code:
sf::Vector2f PinkLocation=PinkPlayer.getPosition();
   if (PinkLocation >= sf::Vector2f(100, 100)){
                     //do stuff
      }
I know that it can't take the two numbers a time, but it there another way to do this?

[shadowmouse]

What exactly would you expect >= to do? Either number being bigger? Both bigger? Longer hypotenuse? Just write your own function that takes two Vector2fs.

[Hapax]

If it's a specific member, you simply just test that specific member you want to test (i.e. x or y).
If it's either number, you can test them both and OR them together.
If it's both, you can just test both and AND them together.

Why do you need to do this?
If it's to see if it's outside of a certain area, it might make more semantic sense (and possibly less code) to see if it's inside an sf::Rect instead.

[GAMINGBACON97]

how would I go about testing a specific number using x and y? and I need it so once you drag something off to a specific direction, then it will increment a score

[GAMINGBACON97]

I think I figured out how to get a specific coordinate, like x or y, I will post an edit once I do some more testing to see if I can close this

[Hapax]

how would I go about testing a specific number using x and y?

PinkLocation.x >= 100

I need it so once you drag something off to a specific direction, then it will increment a score

Is that direction to the right? Then test x. Is that direction to the bottom? Then test y.

[GAMINGBACON97]

Thx Hapax, with your help, and a bit of tweaking I got it working, Thx to all who helped!!!