Check if sf::RectangleShape contains mouse global bounds?

[steven_g]

Hi,
I want to check if an sf::Shape contains the mouse's global bounds (and if left mouse button is clicked), and created the function below:

bool isRectClicked(sf::RectangleShape &rect, sf::RenderWindow &window) {
        sf::IntRect rect(rect.getPosition().x, rect.getPosition().y, rect.getGlobalBounds().width,  
        rect.getGlobalBounds().height);
        if (rect.contains(sf::Mouse::getPosition(window)) && (sf::Mouse::isButtonPressed(sf::Mouse::Left))) {
                return true;
        }
        return false;
}
 

However it says sf::RectangleShape has no member contains. How would I do this or do I have to do it the longer way by checking if the cursor is within the shape dimensions?

[G.]

You should avoid calling 2 different variables with the same name.
"sf::RectangleShape &rect" and "sf::IntRect rect"

[Laurent]

Why don't you just use rect.getGlobalBounds() directly anyway?

[Hapax]

Remember to map the mouse position into the view's co-ordinates.

"Luckily" that returns a Vector2f so you can easily check to see if the rectangle shape's global bounds contains that point.

(click to show/hide)

sf::RenderWindow window;
sf::RectangleShape rect;
if (rect.getGlobalBounds().contains(window.mapPixelToCoords(sf::Mouse::getPosition(window)))
    std::cout << "Rectangle shape contains mouse position." << std::endl;