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Author Topic: fastest way to get pixel from RenderTexture?  (Read 7338 times)

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NinjaFighter

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fastest way to get pixel from RenderTexture?
« on: May 27, 2012, 09:03:35 pm »
I don't know how to Get a pixel information of a RenderTexture, without copy it on a new Image. There's a way to do this more faster?

Laurent

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Re: fastest way to get pixel from RenderTexture?
« Reply #1 on: May 27, 2012, 09:48:25 pm »
There's no way, the texture lives in the graphics card's memory, you have to copy it in an image in system memory to read a pixel.

Why do you need to read pixels of a render-texture?
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NinjaFighter

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Re: fastest way to get pixel from RenderTexture?
« Reply #2 on: May 28, 2012, 05:18:43 am »
It's just curiosity, because I remember that old versions uses myRenderImage.Image.GetPixel() for that purpose. So, in old versions do you store for (each Image instance) a Texture and another Image for Set/Get pixel purposes?
I don't want to use GetPixel now, but I think could be useful for some graphics editing application.
I repeat, it's only curiosity. This is not crucial for me.  :)

eXpl0it3r

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Re: fastest way to get pixel from RenderTexture?
« Reply #3 on: May 28, 2012, 08:09:50 am »
Depending on what you're doing, I guess it's faster to work directly with a sf::Image instead of a sf::RenderTexture and then just call Update(...) on a sf::Texture.
But if you need to do some shape/image rendering, I guess you'll have copy the texture to an image.
If you want to create a graphics editing application I bet there are better libraries for that. ;)
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Laurent

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Re: fastest way to get pixel from RenderTexture?
« Reply #4 on: May 28, 2012, 10:30:00 am »
In SFML 1.6, the Image class was maintaining a copy of the pixel data both in graphics and system memory. When one was outdated, it performed an automatic copy -- so GetPixel could be very slow.

That's why things are now split in two classes :)
Laurent Gomila - SFML developer

NinjaFighter

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Re: fastest way to get pixel from RenderTexture?
« Reply #5 on: May 28, 2012, 08:23:07 pm »
Ah... this make sense now. Thats 100% clear my doubts. Thanks  :)