Problem with inheritance from Drawable

[cristaloleg]

I'm trying to create this class from Drawable, but I get:

error C2259: 'Triangle' : cannot instantiate abstract class in Visual Studio 2008
I'm using sfml 1.6
This is my code. Thank's for any help.

class Triangle : public sf :: Drawable
{
public:
        Triangle () { };
        Triangle ( sf::Vector2f Pos, sf::Vector2f Scale, float Rotation, sf::Color Color ) { };
        ~Triangle () { };
        void Render ( sf :: RenderTarget& Target ) { };
};
 

[FRex]

How this fits in C forum is beyond me..
Render should have virtual in front of void.
D-tor too but it's less important and doesn't stop program from compiling.

[Laurent]

Have a look at the sf::Drawable class and use the exact same prototype for Render.

Render should have virtual in front of void.

It is optional, it wouldn't change anything. A function declared virtual in a base class is implicitely virtual in derived classes.

[FRex]

I never realized that.
Since you gotta redeclare so there is no jumping across bases to find if function exists or not I assumed virtual is supposed to be there..
Well, op is missing const then.

[Nexus]

Render should have virtual in front of void.

It is not required, but good practice to see directly (without base class lookup) if a function is virtual.

D-tor too but it's less important and doesn't stop program from compiling.

The destructor should not even be declared here, since it is empty (and virtual anyway).

Furthermore, cristaloleg might decide if he prefers spaces around the scope operator or not

[cristaloleg]

Thank's for everybody, but I'm still getting compilation error.

Have a look at the sf::Drawable class and use the exact same prototype for Render.

In SFML-1.6 Drawable.hpp

virtual void Render(RenderTarget& Target) const = 0;

So I write in my code(redeclaring virtual function Render)

void Render ( sf :: RenderTarget& Target ) { };

But I don't understand where is error. Can You provide some code for me?
Thank's

[Laurent]

Don't you see that const in the prototype?

[cristaloleg]

Don't you see that const in the prototype?

Unbelievable! I never used code like this. Thank's You very much for everybody.

[Nexus]

Unbelievable! I never used code like this.

The const says that the method doesn't change the object.

I recommend to work with it, too, const-correctness is a very powerful concept. Read the corresponding chapter of your C++ book