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You should really not do this. Just create your own library.
Why do you want to do that?
#include <SFML/System.hpp>
int main()
{
sf::AClock Clock;
//Do something with clock
return 0;
}
Most of these problems can be solved with the Pythagorean theorem and simple sin/cos/tan. This is no exception (If I understand your question correctly, you can actually do this problem without PT explicitly). You need to make a right triangle using one of the tilted sides of your rotated rectangle as the hypotenuse and then solve that triangle.
In SFML, sprites rotate around the upper-left pixel (also it's position) by default. So use that as the known point and make with an adjacent side to make a solvable triangle which will also give you the x and y offsets from the known rotation point. Then you can use the symmetry of the rectangle to solve for any side you care about.
If you still can't get it, post what you've tried. Maybe an MSPaint drawing of how you're trying to solve this problem. (You'll learn a lot more by fighting through these problems instead of just c+p'ing code if I were to just post the solution.)
I'm going to visit a religious community in a couple of hours and will be there until Monday afternoon, but I might be able to pop in at some point to answer questions. If not, hopefully someone else can pick it up and help you figure this out.
Do you know how to use the Pythagorean theorem? If not, google it and see if that helps.
Make a right triangle with the tilted rectangle and use Pythagoras's Theorem.
#include <SFML/Graphics.hpp>
int main(int argc, char *argv[])
{
sf::RenderWindow RenderWindow(sf::VideoMode(800,600,32),"Test");
sf::Event Event;
bool Loop = true;
while(Loop)
{
while(RenderWindow.GetEvent(Event))
{
if(Event.Type == sf::Event::Closed)
Loop = false;
}
RenderWindow.Display();
}
}
The two last parameters are right and bottom, not width and height :Code: [Select]return sfIntRect(sprite.GetLeft(),sprite.GetTop(),sprite.GetLeft()+sprite.GetWidth(),sprite.GetTop()+sprite.GetHeight());
class Sprite
{
public:
sfIntRect GetRect()
{
return sfIntRect((sprite.GetLeft(),
sprite.GetTop(),
sprite.GetLeft()+sprite.GetWidth(),
sprite.GetTop()+sprite.GetHeight());
}
};
class Ball : public Sprite {}
class Paddle : public Sprite {}
void HandleBallToPlayerCollision()
{
if( paddle->GetRect().Intersects(ball->GetRect()))
{
//Do stuff if collided
}
}
sprite.GetSubRect will give you coordinates relative to the image, you have to offset it by the position of the sprite.
sfIntRect GetRect()
{
return sfIntRect(sprite.GetLeft(),sprite.GetTop(),sprite.GetWidth(),sprite.GetHeight());
}
class Sprite
{
public:
sfIntRect GetRect(){ return sprite.GetSubRect(); }
//.....
private:
sfSprite sprite;
//.....
};
class Paddle : public Sprite
{
//.....
}
class Ball : public Sprite
{
//.....
}
bool Intersects(const sfRect<T>& Rect, sfRect<T>* OverlappingRect = NULL) const;
void HandleBallToPlayerCollision()
{
if( paddle->GetRect().Intersects(ball->GetRect()))
{
// Do stuff here.....
}
}
Quote from: "Mindiell"I don't think this is the good solution. What you do is having a 100x100 image and taking only the first 50x50 part...
My first question is :
- Why are you using the same sprite to draw 2 images ?
I was going to have questioned his methods but I thought I'd rather provide a working and very valid solution to his problem, in the style of his code to save arguement.
Although I do agree with you that the simple solution is to create a new Sprite for each image.